You are given a two-dimensional 3*3 array starting from A [0][0]. You should add the alternate elements of the array and print its sum. It should print two different numbers the first being sum of A 0 0, A 0 2, A 1 1, A 2 0, A 2 2 and A 0 1, A 1 0, A 1 2, A 2 1.

Question:

You are given a two-dimensional 3*3 array starting from A [0][0]. You should add the alternate elements of the array and print its sum. It should print two different numbers the first being sum of A 0 0, A 0 2, A 1 1, A 2 0, A 2 2 and A 0 1, A 1 0, A 1 2, A 2 1. 

 

Input Format 

 

First and only line contains the value of array separated by single space. 

 

 

Output Format 

 

First line should print sum of A 0 0, A 0 2, A 1 1, A 2 0, A 2 2 Second line should print sum of A 0 1, A 1 0, A 1 2, A 2 1 

 

SAMPLE INPUT  

 

1 2 3 4 5 6 7 8 9 

 

SAMPLE OUTPUT  

 

25 20 

Answer:

#include <stdio.h>

int main()

{

    int a[3][3], odd_sum=0,even_sum=0;

    for(int i=0;i<3;i++)

    {

        for(int j=0;j<3;j++)

        {

            scanf("%d",&a[i][j]);

        }

    }

    

    for(int i=0;i<3;i++)

    {

        for(int j=0;j<3;j++)

        {

            if((i+j)%2==0)

               even_sum=even_sum+a[i][j];

            else

                odd_sum=odd_sum+a[i][j];

        }

    }

    

    printf("%d\n",even_sum);

    printf("%d\n",odd_sum);

    return 0;

}

OUTPUT:

1 2 3 4 5 6 7 8 9                                                                                          

25                                                                                                         

20